(19-01-17, 09:34 PM)ahmed.nabil كتب : Dim exlapp As New Application
       Dim exlworkbook As Workbook
       Dim exlworksheet As Worksheet
       Dim misvalue As Object = System.Reflection.Missing.Value
       exlworkbook = exlapp.Workbooks.Add(misvalue)
       exlworksheet = exlworkbook.Sheets("Sheet1")
       For colhead As Integer = 1 To DataGridView1.ColumnCount - 1
           exlworksheet.Cells(1, colhead + 1) = DataGridView1.Columns(colhead).HeaderText
       Next
       For i As Integer = 0 To DataGridView1.RowCount - 1
           For j As Integer = 1 To DataGridView1.ColumnCount - 1
               exlworksheet.Cells(i + 2, j + 1) = DataGridView1.Rows(i).Cells(j).Value.ToString
           Next
       Next
       sfd1.FileName = ""
       sfd1.Filter = "Excel 2003| *.xls | Excel 2007| *.xlsx "
       If sfd1.ShowDialog = System.Windows.Forms.DialogResult.OK Then
           exlworksheet.SaveAs(sfd1.FileName)
       Else
           Exit Sub
       End If
       exlworkbook.Close()
       exlapp.Quit()
       System.Runtime.InteropServices.Marshal.ReleaseComObject(exlapp)
       System.Runtime.InteropServices.Marshal.ReleaseComObject(exlworkbook)
       System.Runtime.InteropServices.Marshal.ReleaseComObject(exlworksheet)
       exlapp = Nothing
       exlworkbook = Nothing
       exlworksheet = Nothing
       If MsgBox("Do You Want To Open File ", MsgBoxStyle.YesNo) = MsgBoxResult.Yes Then
           Process.Start(sfd1.FileName)
       End If
ده كود شغال معايا تمام وبيخرج الاكسل ومفيش اي مشكلة جربو