07-03-18, 06:56 PM
جربت هذه الطريقة
ويطلع لي خطأ في بناء جملة UPDATE
ويطلع لي خطأ في بناء جملة UPDATE
PHP كود :
Dim xy As String
If RadioButton2.Checked = True Then
xy = 1
ElseIf RadioButton1.Checked = True Then
xy = 0
Else
Exit Sub
End If
Dim str As String = "update tb_info set [info_name]=@info_name, [info_phon]=@info_phon,[info_email]=@info_email,[info_city]=@info_city,[info_job]=@info_job,[info_tr]=@info_tr,[info_tr_sys]=@info_tr_sys,[info_tr_bank]=@info_tr_bank,[info_tr_bname]=@info_tr_bname,[info_tr_prog]=@info_tr_prog,[info_date]=@info_date, WHERE [info_id]=@info_id"
Dim erw As New OleDbCommand(str, con)
erw.Parameters.AddWithValue("@info_id", Label7.Text)
erw.Parameters.AddWithValue("@info_name", TextBox1.Text)
erw.Parameters.AddWithValue("@info_phon", TextBox2.Text)
erw.Parameters.AddWithValue("@info_email", TextBox4.Text)
erw.Parameters.AddWithValue("@info_city", TextBox5.Text)
erw.Parameters.AddWithValue("@info_job", TextBox6.Text)
erw.Parameters.AddWithValue("@info_tr", xy)
erw.Parameters.AddWithValue("@info_tr_sys", ComboBox1.Text)
erw.Parameters.AddWithValue("@info_tr_bank", ComboBox2.Text)
erw.Parameters.AddWithValue("@info_tr_bname", TextBox13.Text)
erw.Parameters.AddWithValue("@info_tr_prog", ComboBox3.Text)
erw.Parameters.AddWithValue("@info_date", DateTimePicker1.Value.Date)
con.Open()
erw.ExecuteNonQuery()
MsgBox("تم التحديث")
