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لعمل password عشوائية
#1
كاتب الموضوع : AhmedEssawy

الشرح ضمن الكود :


كود :
CREATE PROC random_password
(
@len int = 8, --Length of the password to be generated
@password_type char(7) = 'simple'
--Default is to generate a simple password with lowecase letters.
--Pass anything other than 'simple' to generate a complex password.
--The complex password includes numbers, special characters, upper case and lower case letters
)
AS
/***********************************************
Examples:
To generate a simple password with a length of 8 characters:
EXEC random_password
To generate a simple password with 6 characters:
EXEC random_password 6
To generate a complex password with 8 characters:
EXEC random_password @Password_type = 'complex'
To generate a comples password with 6 characters:
EXEC random_password 6, 'complex'
***********************************************/
BEGIN
DECLARE @password varchar(25), @type tinyint, @bitmap char(6)
SET @password=''
SET @bitmap = 'uaeioy'
--@bitmap contains all the vowels, which are a, e, i, o, u and y. These vowels are used to generate slightly readable/rememberable simple passwords
WHILE @len > 0
BEGIN
IF @password_type = 'simple' --Generating a simple password
BEGIN
IF (@len%2) = 0 --Appending a random vowel to @password
SET @password = @password + SUBSTRING(@bitmap,CONVERT(int,ROUND(1 + (RAND() * (5)),0)),1)
ELSE --Appending a random alphabet
SET @password = @password + CHAR(ROUND(97 + (RAND() * (25)),0))
END
ELSE --Generating a complex password
BEGIN
SET @type = ROUND(1 + (RAND() * (3)),0)
IF @type = 1 --Appending a random lower case alphabet to @password
SET @password = @password + CHAR(ROUND(97 + (RAND() * (25)),0))
ELSE IF @type = 2 --Appending a random upper case alphabet to @password
SET @password = @password + CHAR(ROUND(65 + (RAND() * (25)),0))
ELSE IF @type = 3 --Appending a random number between 0 and 9 to @password
SET @password = @password + CHAR(ROUND(48 + (RAND() * (9)),0))
ELSE IF @type = 4 --Appending a random special character to @password
SET @password = @password + CHAR(ROUND(33 + (RAND() * (13)),0))
END
SET @len = @len - 1
END
SELECT @password --Here's the result
END
}}}}
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المواضيع المحتمل أن تكون متشابهة .
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